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Sunday 10 March 2013

JAVA PROGRAM: TO FIND SUM OF DIGITS OF A NUMBER



CODING OF ACTION BUTTON(jButton1)
        int num,temp,sum = 0;
        num=Integer.parseInt(jTextField1.getText());
            while(num>0)
            {
                temp=num%10;
                sum+=temp;
                num=num/10;
            }
            jTextField2.setText(" "+sum);


CODING OF CLEAR BUTTON(jButton2)
        jTextField1.setText(" ");
        jTextField2.setText(" ");
   

CODING OF EXIT BUTTON(jButton3)   
        System.exit(0);


CODING

RUNNING

We have used NetBeans IDE 7.2.1. To download it visit www.netbeans.org


For any query or suggestion please comment below...

2 comments:

  1. thanks for the code!
    can you just explain it to me roughly

    ReplyDelete
    Replies
    1. Using "temp=num%10;" we got the remainder i.e. last digit of number "num". Then we added it to "sum" ("sum" is 0 at starting) using "sum+=temp;". Now we will remove last digit of number by "num=num/10;" . We will repeat this until "num" is 0.

      Hope you understood. If you have any doubt please feel free to ask.

      Delete