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Friday 1 March 2013

C PROGRAM: TO MULTIPLY TWO NUMBERS WITHOUT USING ARITHMETIC OPERATOR *

CODING:
#include<conio.h>
#include<stdio.h>
void main()
{
 int num1,num2,i,prod=0;
 clrscr();
 printf("Enter 1st number: ");
 scanf("%d",&num1);
 printf("Enter 2nd number: ");
 scanf("%d",&num2);
 for(i=1;i<=num2;i++)
 {
  prod+=num1;
 }
 printf("\n\n\nProduct of %d and %d is %d",num1,num2,prod);
 getch();
}


CODING

OUTPUT


For any query or suggestion please comment below...

4 comments:

  1. A much better method using bit manipulation(IN C++)

    #include
    using namespace std;
    int main()
    {
    int a,b,c,i;
    cin>>a>>b;
    if(a>=1,i++)
    {
    if(b&1)c+=(a<<i);
    }
    cout<<c;
    return 0;
    }

    ReplyDelete
  2. Yes ok.But you are used + operator.So we can use sum+=i

    ReplyDelete
  3. it doesnt work because when we enter negative integer it counts as 0

    ReplyDelete
  4. This method is suitable for not all values, input 2,-3
    Getting output is 0.
    So how to solve this..

    ReplyDelete